DSH 525 Applied force for internal parts

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DSH 525 7 O3 S7 q  h- [9 H. k

Applied force for internal parts ! i* @7 T/ I$ K0 h" {! m$ x  R% v

13.2 * z% _4 t  {. O$ a- C

60065(ed.6) ; Z+ [: D% v3 E$ s4 s

! P: j( ^: e: JStandard:
, B0 g* I. s, v2 m  dIEC60065 6ed.
Sub clause:
( w2 k5 i) s2 V# ]13.2
0 Q2 z. Y, ?' m+ I0 z8 fSheet No.
. K5 w. [7 y( b  T525
) _6 i4 c% u  S9 u6 I$ H# OSubject
Applied force for internal parts
8 }. _, Q( q$ `% mKey words:
5 d6 }/ k# _6 D4 z0 s' Yforce for internal parts
+ N+ H$ \* o2 |3 MDecision taken at the
! H0 c  T5 j- l9 d40th meeting 2003
* I# i9 y0 [. K% ^Question:
7 z" Z# a0 m, E( v7 B& f2 Z( ~In clause 13.2, it is specified that 2N for internal parts and 30N for the outside are applied
simultaneously while taking measurement of clearance. However, it is not specified that forces are
applied to internal parts while taking measurements between two internal parts, ex. primary circuit
component and secondary circuit component.
/ e% I9 ?4 ?7 u! E1 IWhich is the appropriate method to measure clearance between two internal parts ?
- b) A9 W3 C+ z. c. qa) 2N forces are applied to the both parts simultaneously.
b) First, a 2N force is applied to one part and removed. And then a 2N is applied to the other one.
c) Other opinion
8 F# `9 `0 l9 }8 g' F1 a$ N1 x4 hDecision:
First, a 2N force is applied to one part and removed. Then a 2N force is applied to the other
8 W) z) `! \0 q4 _7 ]part.


5 i  k% v; A+ x! \( I! {