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9 @, n; a5 t8 o2 y) v) _, b/ T | Figure 21, presence of resistor of 45 kO
6 p) j5 P5 P* N% I0 q; N | 196 u3 y2 L3 M; b8 M T9 W% R0 ^
| 60601-1(ed.2);am1;am2' [; U% Y+ R% N1 t
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9 q2 D+ ~7 `* U! ]3 U9 I' E( dStandard(s)- (year and edition):
* Q3 d% c, _- X; R( Y7 zIEC 60601-1:1988 Ed.2
5 E% p; B3 \# |Am1+Am2
6 f% g* J6 [8 j q% s& {Sub clause(s):
j* v" C1 U% @; g# b5 ?% z19
' T3 K2 u" P( b: g6 H/ @9 U G$ kSheet n°: 534
7 _0 m2 g9 ]. x- f) U+ U# eSubject:7 k7 w$ w2 {$ O. D3 ?' W
Figure 21, presence of resistor
& u. M8 s/ X+ r6 R" `of 45 kO7 M: V4 n, g% p6 E- f
Key words: Decision taken at the 40th4 U' n3 Q4 X5 G# h) ~4 S6 d
meeting 2003
% E) z, x0 C2 w5 D- _+ K& Q6 B0 vQuestion:5 p& ^) s% E6 E( @
Should the 45 kO resistor be used since the current is limited to 5 mA and the limit is 5 mA?# [4 {3 m! L% y9 o, E4 Y" B: E- ~
Decision:' P% p7 r" X3 B" W4 ]& c9 ~) x
For the 1st edition, use the method of 2nd edition (use any resistance).4 t5 Q- _0 D+ n4 f
For 2nd edition, instead of using any resistance, you may also use alteration of the voltage or fuses.$ R2 `3 B0 q( w0 r K' ]
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