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|  DSH 525# }/ G7 u! P" z
C! U0 a- w& R( I j8 z | Applied force for internal parts' C, p& v/ {/ [7 J; |! o/ Q
| 13.2
# Z6 G' I$ O% F ?% Q | 60065(ed.6)/ G6 k2 b/ ?1 {
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Standard:8 q f) @0 O. E( m
IEC60065 6ed.
N8 L: O( j9 ^3 C% [, y! `& d5 sSub clause:& G2 ]4 c, K% m( y2 l
13.2, p+ W* L3 z- Y+ y; j7 _
Sheet No.2 ^; e/ P0 F9 `8 R( p* w
525. F% v" u: ?! g8 w8 S. Z1 i
Subject
. p5 v! P8 F- }; J+ i9 fApplied force for internal parts
: n+ ?; i: ]! w6 @. k4 G# hKey words:
6 Q4 {5 \8 U; w" O! ]4 w+ lforce for internal parts7 _! e2 F; b" L" V5 G
Decision taken at the& t: d6 p! E" Y
40th meeting 2003) w5 `2 a( @) b; Y3 X, L
Question:. i9 F% z/ Z- l& i
In clause 13.2, it is specified that 2N for internal parts and 30N for the outside are applied4 h2 P6 m5 U0 Q5 j+ s6 t3 x3 P
simultaneously while taking measurement of clearance. However, it is not specified that forces are
P/ I& u+ q' @4 I) k4 happlied to internal parts while taking measurements between two internal parts, ex. primary circuit
& ?; O0 f) ~# |) f! @2 fcomponent and secondary circuit component.5 A( y: F: b) e( f% @, ]% S( q- o
Which is the appropriate method to measure clearance between two internal parts ?" S7 C8 Z8 J. r7 ]% Z8 H# @
a) 2N forces are applied to the both parts simultaneously.6 ]- A, r' p$ H3 X) }; w
b) First, a 2N force is applied to one part and removed. And then a 2N is applied to the other one.5 S% L2 {6 m* e. E
c) Other opinion
$ {; o& n# \0 \% _0 sDecision:1 P5 U& n$ [) j: O8 o9 m' g ]8 s
First, a 2N force is applied to one part and removed. Then a 2N force is applied to the other% [& \3 t6 T. q) v; z1 S5 ]
part.
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发表于 2012-11-8 18:42
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