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| Figure 21, presence of resistor of 45 kO- ^7 c4 W1 m6 a2 S6 v B
| 19/ ~* e) D. }' S+ f2 P) y0 @
| 60601-1(ed.2);am1;am2
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' b# Z# ^% o/ B) H: |Standard(s)- (year and edition):
5 O1 f0 H' [3 ]5 Q+ z3 l iIEC 60601-1:1988 Ed.2
4 y( e( ~( _# g S9 H* Q* T0 wAm1+Am2& [: {/ N! f ~7 {7 g! g9 X
Sub clause(s):0 U* s: ^3 q* ]
19% H) r- D5 w- U! v# a$ S
Sheet n°: 534
9 `! w8 p+ V4 m% F7 Y% x% h) F5 DSubject:
/ I* d, ?! ~/ f& P8 _Figure 21, presence of resistor
4 ^% g8 y; @( z' hof 45 kO
3 Z7 e* W" G" |/ I8 j3 zKey words: Decision taken at the 40th
+ P- A6 Z1 V( a' f" jmeeting 2003$ s- j( v1 F( E
Question:( o, m* \& U" k5 t' K
Should the 45 kO resistor be used since the current is limited to 5 mA and the limit is 5 mA?& @, d3 ` N+ F
Decision:
8 C! f! U- K# f* V" u. \# dFor the 1st edition, use the method of 2nd edition (use any resistance).$ d; f) T, Y- v7 O4 L( w1 W# ^
For 2nd edition, instead of using any resistance, you may also use alteration of the voltage or fuses.- S( f$ X7 [1 P; |4 \' o
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发表于 2012-9-19 15:49
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