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| DSH 525
1 _1 I) y3 N6 p% P N) f& p. e; E, @; O
| Applied force for internal parts; x, w' u. x( g: B
| 13.2
. c) B2 ^& @3 ?' E: k | 60065(ed.6)- Q0 `9 V9 L+ [3 p- T
|
" b' n* o& d* D; X- Z1 fStandard:0 C+ G0 s6 Z3 \* G9 [' q/ N! a
IEC60065 6ed.
* T0 O+ a, c9 M1 b) i/ {Sub clause: f$ E( l; \5 f( }- L
13.24 k# {$ A7 v0 J
Sheet No.
( b4 I+ O. N. ^( H, m q0 p9 P525- T3 d2 r) U+ @/ o5 ^
Subject7 [2 h+ Q0 ]7 T/ v( L
Applied force for internal parts
2 V" k) H r+ o7 {) PKey words:+ } Q: n" ]! i
force for internal parts
" B; g0 _; W0 p K c( W6 r) M+ YDecision taken at the: f3 |7 a& U. G5 x' W
40th meeting 2003
6 G u3 l V; X. Z g- y( M9 hQuestion:
5 c( l7 G* w/ b, f+ K3 _0 pIn clause 13.2, it is specified that 2N for internal parts and 30N for the outside are applied
- U) t" R+ U2 G* @) n6 q: e" |+ zsimultaneously while taking measurement of clearance. However, it is not specified that forces are3 U: @2 R9 S5 i4 T% O. l1 M3 ~
applied to internal parts while taking measurements between two internal parts, ex. primary circuit
( \3 h! j2 s5 _% C g4 @component and secondary circuit component.
* T% R% _% T3 eWhich is the appropriate method to measure clearance between two internal parts ?- q3 | z/ w9 N
a) 2N forces are applied to the both parts simultaneously., X) \$ w3 x( F4 h) f+ A
b) First, a 2N force is applied to one part and removed. And then a 2N is applied to the other one.6 `5 L9 ~! q1 B# V5 p: x
c) Other opinion
8 z) N! y, r& d$ e4 NDecision:
0 p7 o- A! u" nFirst, a 2N force is applied to one part and removed. Then a 2N force is applied to the other
) w: L- n) q$ r1 }" f' Wpart.
8 w. c1 k9 `. B' U8 r$ D# R. w- G% i+ @/ o' K5 i$ }9 H
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