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引用第10楼franco于2009-05-07 20:39发表的 :
9 s& V& q/ m" I! aThe oscillating member is moved backwards and forwards through an angle of 90° (45° on ! k. z0 N) I3 w# f
either side of the vertical), the number of flexings being 20 000 and the rate of flexing 60 per
7 r. p+ l# r0 X, b p+ hmin. A flexing is one movement, either backwards or forwards. After 10 000 flexings, the
* [' j# w% B2 b" h+ Wsample is turned through 90° about the centre line of the cord guard.
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( g1 I& j! m* m& }....... 是的,这段话写的确实很明白,但是我估计你还是理解错了。
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翻译成中文的主要意思就是:
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4 Q: H! c# _# C$ O$ \The oscillating member is moved backwards and forwards through an angle of 90° (45° on & g. J+ S: K$ `# P& n5 p- p
either side of the vertical), the number of flexings being 20 000 and the rate of flexing 60 per
1 }& d( Z/ Y( K! _3 m/ ~min. - 摇摆装置能够在90°的范围内前后摆动(其中这个90°指的是沿垂直位置两边各45°),以每分钟60次的频率摇摆20000次。
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% `8 F! b# c! M- {这句话讨论的是仪器的摆动机构要满足的特性,就是要能在90°的范围内前后摆动,如果只能在45°的范围内摆动的话,这个设备就是不符合要求的。这句话并没有涉及到一个摆动周期如何定义啊。
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+ q3 ?7 s. u x: T5 {$ U# I) [+ ]After 10 000 flexings, the sample is turned through 90° about the centre line of the cord guard. - 10000次摆动之后,将样品沿着电线防护套的中心线转动90°。
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4 N1 }$ q8 ]5 r这句话说的是总共20000次的摆动样品应该在两个位置分两次完成而已,同样没有涉及到摆动周期的解释和说明。
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% G$ k# P. c0 c, ~4 i9 F1 J0 D最重要的一句话应该是:A flexing is one movement, either backwards or forwards. - 一次摇摆就是一次移动,无论是向后还是向前的。
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, n1 j! }5 o' L这句话虽然容易引起歧义,但是仔细考虑一下也不是很难理解。可以看出,1个摆动周期就是单次的向前或者向后的移动。摇摆机构是在总共90°范围内摆动,那不管是向前还是向后的摆动角度都是45°了。由此可以得出1个摇摆周期就是45°而不是我们通常认为的90°。
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5 O# b4 X& R, U% R' k摘抄UL 745-1标准中的相关章节如下,关于这个问题解释的非常清楚,供大家参考参考:+ P3 \9 X! h1 {( E
2 W/ `* ]; b! k+ TA flexing is one movement, either backwards or forwards. That is, from vertical to 45° in one direction is the first flex, from there back to vertical is the second flex, from vertical to the opposite 45° is the third flex, from there back to vertical is the fourth flex, continuing until 10000 flexes have occurred. |
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