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49 Component Power Measurement Test8 }: X* S+ y! |4 e2 b6 D
49.1 To determine if a component or a circuit of a seasonal lighting product is capable of delivering 15
2 x7 k3 ~" S2 U) c( [watts of power for one minute (see 48.1, Exception No. 1(c)), the component shall be tested as described
+ s- `; Z2 u! Y z( w% Tin 49.2 – 49.4., l3 {+ L. T3 @1 f
49.2 The unit is to be connected to a 60 Hz, 120 V supply source. One component or circuit of the unit
) \, f9 u7 ?6 @1 d# wis to be connected to a wattmeter and an adjustable external load resistor as illustrated in Figure 49.1.+ q( I f+ e" S, M
The external load resistor is to be set for its maximum resistance. A closed shorting switch is to be
' W3 ]. y: V& n' w" cconnected across the unit’s protective device, such as a fuse, and the resistor is then to be adjusted to5 V8 T! a0 z5 a4 j
cause a power dissipation of exactly 15 watts as indicated by the meter. The shorting switch across the# l( r* \4 C" k' r( ?7 f% j
protective device is then to be opened and the time required for the protective device to open is to be
) d# _: ?( c/ o" a3 y1 |recorded., `- }6 {, k, N, i% }: o, b) Y& y
49.3 During the test, the supply circuit is to be protected by a 20 A time delay fuse, with characteristics' W; J8 Z# G2 q, J4 z x' Q
such that the fuse will not open in less than 12 seconds when carrying 40 A.
j3 b, w& p- L0 D49.4 The point of measurement of the circuit (see Figure 49.1) is not considered capable of delivering 15
0 t7 L9 W" r7 f* z+ \" Cwatts for one minute if:. d9 P: S% U- i+ s; P% l* ]
a) The protective device of the unit opens in less than 60 seconds,3 J$ a+ J( A. [. B O
b) A circuit component opens in less than one minute, or
/ r% i/ I9 t( w2 s: ac) The current is inherently limited by the circuit. |
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发表于 2010-8-6 13:51
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