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49 Component Power Measurement Test$ Q; V7 B5 l5 @* m/ \8 I* h
49.1 To determine if a component or a circuit of a seasonal lighting product is capable of delivering 151 o8 a5 i7 `' L. }3 P! n
watts of power for one minute (see 48.1, Exception No. 1(c)), the component shall be tested as described3 G: y' j8 y0 t" f
in 49.2 – 49.4. @' y' T- r+ r
49.2 The unit is to be connected to a 60 Hz, 120 V supply source. One component or circuit of the unit% K4 b$ Z: {2 r, @ m; O( c
is to be connected to a wattmeter and an adjustable external load resistor as illustrated in Figure 49.1.
9 C. b0 g9 O6 }+ {; ?+ O! e; t9 vThe external load resistor is to be set for its maximum resistance. A closed shorting switch is to be
4 J8 K- l! h; r5 o0 rconnected across the unit’s protective device, such as a fuse, and the resistor is then to be adjusted to
. B4 E7 ~4 z# ?0 tcause a power dissipation of exactly 15 watts as indicated by the meter. The shorting switch across the
; { v5 {. N- Y3 ^9 t1 ?protective device is then to be opened and the time required for the protective device to open is to be( P- ]# B; O" \
recorded., R8 F/ Y2 {' A, d; w6 _
49.3 During the test, the supply circuit is to be protected by a 20 A time delay fuse, with characteristics {, \! z& S5 `% ~- b% f$ V
such that the fuse will not open in less than 12 seconds when carrying 40 A.
. G9 S Y2 C! I$ M/ _ J( s1 ?* a49.4 The point of measurement of the circuit (see Figure 49.1) is not considered capable of delivering 15$ u! s$ e! c0 Q6 @! C
watts for one minute if:8 h6 M/ Q' S; l( z4 k
a) The protective device of the unit opens in less than 60 seconds,
7 Z+ l# ~, f4 v8 C8 J) e G B: N, zb) A circuit component opens in less than one minute, or Y7 `1 U6 C) k" ^
c) The current is inherently limited by the circuit. |
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发表于 2010-8-6 13:51
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