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引用第10楼franco于2009-05-07 20:39发表的 :( I7 W# o" o, q: D% F
The oscillating member is moved backwards and forwards through an angle of 90° (45° on # {' {) m& r% X7 P' O$ O1 n7 ?7 c! i
either side of the vertical), the number of flexings being 20 000 and the rate of flexing 60 per
" h" B7 y( O$ ~8 q( Y" e; _/ Emin. A flexing is one movement, either backwards or forwards. After 10 000 flexings, the
% K7 L3 L0 q0 X, Ssample is turned through 90° about the centre line of the cord guard. ' A- ~: |! u! Q/ R* z! \. b
9 a; j- f ^% h; l) T! e....... 是的,这段话写的确实很明白,但是我估计你还是理解错了。; R l3 `( P, T+ e9 l, ^
. B7 N# I. h/ j7 H5 {翻译成中文的主要意思就是:
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The oscillating member is moved backwards and forwards through an angle of 90° (45° on $ @" y4 @/ {9 }7 B! z9 V, d
either side of the vertical), the number of flexings being 20 000 and the rate of flexing 60 per
# L3 j7 y' g1 L1 }9 bmin. - 摇摆装置能够在90°的范围内前后摆动(其中这个90°指的是沿垂直位置两边各45°),以每分钟60次的频率摇摆20000次。
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* o, T! G5 O7 R4 a这句话讨论的是仪器的摆动机构要满足的特性,就是要能在90°的范围内前后摆动,如果只能在45°的范围内摆动的话,这个设备就是不符合要求的。这句话并没有涉及到一个摆动周期如何定义啊。
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After 10 000 flexings, the sample is turned through 90° about the centre line of the cord guard. - 10000次摆动之后,将样品沿着电线防护套的中心线转动90°。" D, Y+ `. M2 t. {
3 e) A$ t! \7 w" z9 L1 p这句话说的是总共20000次的摆动样品应该在两个位置分两次完成而已,同样没有涉及到摆动周期的解释和说明。 r o, j7 h$ j/ n5 W: e
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最重要的一句话应该是:A flexing is one movement, either backwards or forwards. - 一次摇摆就是一次移动,无论是向后还是向前的。
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这句话虽然容易引起歧义,但是仔细考虑一下也不是很难理解。可以看出,1个摆动周期就是单次的向前或者向后的移动。摇摆机构是在总共90°范围内摆动,那不管是向前还是向后的摆动角度都是45°了。由此可以得出1个摇摆周期就是45°而不是我们通常认为的90°。
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摘抄UL 745-1标准中的相关章节如下,关于这个问题解释的非常清楚,供大家参考参考:
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' j9 D; J* r- F+ Z* b! DA flexing is one movement, either backwards or forwards. That is, from vertical to 45° in one direction is the first flex, from there back to vertical is the second flex, from vertical to the opposite 45° is the third flex, from there back to vertical is the fourth flex, continuing until 10000 flexes have occurred. |
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