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我们一款打草机,在国外遭投诉, 原因是打草线自动切断后,线头飞出,打疼用户的脚趾头.( @. v( b" x6 x3 a& ^7 b1 j) J
问题产品在国外, 看不到, 我觉得原因是如下两点, 请各位帮忙分析对不对:
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' t2 F1 }# D, K3 t- S8 @4 g第一, 护罩尺寸及角度不对, 参见IEC 60335-2-91, 20.101.1 q5 E5 I6 H4 e) ~. A: X0 \
20.101.1 Lawn trimmers
4 H; R3 p1 Y& f W; w0 ULawn trimmers shall be guarded on the operator’s side, as a minimum, to the extent shown
& N9 r T8 N `! \! N! H7 lin Figure 101.
" H# [2 y+ e5 TThe radius X of the guard shall not be smaller than the major swept radius of the cutting
/ e: X0 d7 W2 y# z. o# zhead and the guard shall extend beyond the plane of the cutting element by at least 3 mm: Q3 m I" [! {8 S }8 |
for walk-behind lawn trimmers and 10 mm for hand-held lawn trimmers. The guard shall
, `' T' l" j! `7 n, Eextend at least 45° from the axis of the handle on the side where the cutting element is
0 Y% }9 i9 }) r0 Z) Qmoving away from the operator and at least 90° from the axis of the handle on the side where+ |( x. j. W4 S* T: H# V: k
the cutting element is moving towards the operator. The vertices of these angles lie on the. C$ r0 K% w) a/ J
axis of the cutting head spindle.8 M) P7 M2 i0 v" |4 K" q
If the guarding is less than a total of 360°, the direction of rotation of the cutting element(s)4 ^7 ?) [* D: s. s" i' S' H
shall be marked on the lawn trimmer.: O1 R* B. g/ S* v9 e; ~
Compliance is checked by inspection and measurement.6 ]8 P& h) z# o7 i4 w( Q+ T" U
2 z+ w1 A( `+ C3 j C第二, 飞出线头动能太大. 参见 IEC 60335-2-91, 22.103
9 q7 f# Q2 ^5 A0 X& B1 ~8 E$ |& b22.103 A cutting element shall have a kinetic energy of not more than 10 J.& M/ J" D2 \6 M3 V+ n* F2 O/ g
Compliance is checked by inspection, measurement and test. Polyamide cutting elements, X$ F4 v8 H" e/ Y) n- H! k7 `
are stored for at least seven days in a humidity cabinet under the same conditions as those
+ \. U# h3 q# `* s' y8 a2 Xrequired for the test of 15.3 before carrying out the test and measurement.3 A, n% N/ q, A0 ]6 b+ d8 K6 ^: u) [
For the purposes of this standard, the kinetic energy shall be determined by means of the
* _6 _) @8 h# Z4 Tfollowing formula:
9 n' T( q+ [0 `7 O L) x8 l% U0 dkinetic energy = ½ mv2 (J)
9 `& t7 U7 R( Y0 Hwhere# n, F* l) w/ W( @
m is the mass of the length L of the cutting element, in kilograms (see Figure 105);1 f0 ^* H+ Z* p1 U9 s5 s0 |
v is the maximum attainable velocity of point Z which is half-way along the length L of the9 ] K- B) O; l
cutting element, in metres per second.
2 z/ p$ x6 r3 j6 s9 pTherefore: v = 0,1047 n ( r– (L/2))& L+ T4 G2 ^/ X8 C6 F j; ^
where
' I& w& j5 @0 a5 y3 Z% M# sn is the maximum rotational speed with a full length of line or a new cutter fitted, in- L9 y: o/ m: u. ~: `2 W9 c8 o
revolutions per minute;
! J* v# P% V# Hr is the distance from the axis of rotation of the cutting head to the outer tip of the cutting
`' G, V2 C# [) H1 umeans, in metres;' P9 v2 Z* p# Y5 x8 w) z9 U
L is the measured length of the cutting element, in metres.9 u6 c, Q; [9 ^; j, o* I
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F+ S2 R; W1 ?, r5 ^( L |
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