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求解：标准中有说电量的计算是通过2000 Ω电阻，测出电压/时间曲线，求出电路二端的放电电量。好久没用高数了，对于此电压/时间曲线，如何计算？积分公式是怎样的？ y5 D5 t) K/ N- W0 F2 p* x
3 A4 _0 P( {( x0 fIf protective impedance is used, the current between the part and the supply source shall. x" n% w$ v( R9 }7 ^' p5 T
not exceed 2 mA for d.c., its peak value shall not exceed 0,7 mA for a.c. and
# \: T4 F7 q* T' |* {% e l– for voltages having a peak value over 42,4 V up to and including 450 V, the capacitance0 ^; f+ s- C+ L) C9 `- x+ ~% e
shall not exceed 0,1 μF;
% O5 E& ~! O d% r" P( ]– for voltages having a peak value over 450 V up to and including 15 kV, the discharge shall2 ?- V7 ]2 Y+ R+ g0 \. H
not exceed 45 μC;
$ `1 R: r K) \' M; v( Y7 l* L2 ^– for voltages having a peak value over 15 kV, the energy in the discharge shall not exceed
. U1 N7 D+ A+ V0 L* q4 y& ~" }7 P350 mJ.# t- M" D& K, W. K) f6 [
Compliance is checked by measurement, the appliance being supplied at rated voltage.
/ N3 K6 R* S/ k) A% c1 |7 EVoltages and currents are measured between the relevant parts and each pole of the supply |* X1 y" j) ~* D1 r2 P. l
source. Discharges are measured immediately after the interruption of the supply. The
; i7 ~$ g( u6 i8 D$ q9 `- E& |6 k. ^quantity of electricity and energy in the discharge is measured using a resistor having a8 W& P, ]5 Q B) I* D( w: e
nominal non-inductive resistance of 2 000 Ω .
8 B$ |4 E8 }0 D' [) L" i+ j+ f$ d. p. H* i5 D$ D" Q7 Q
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发表于 2016-8-15 16:43
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