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|  DSH 387" R: N: r- _% e2 E7 j
- r; c& }* f( @. ^
| Hazardous Voltage. w" L+ O; q# W4 }+ B: H
| 1.2.8.3 / 12.8.4
6 g H7 R3 i2 ^# ]1 B | 60950(ed.2) & 60950(ed.3)
* d; P( w' o8 {7 d3 i Z, x. m |
5 O. k& ?( G+ x8 j5 A- A h WStandard:! S$ H# l. u6 g% t( `6 t
IEC60950, 2nd (3rd) Edition6 W3 Y3 r6 T. w
Sub clause:
( {% Z9 k9 V" W0 _- @ c: ~1.2.8.3(1.2.8.4)
* S5 o- E5 ]7 {) H! f* r; {( p, w' TSheet n. 387
/ T; ]1 o T; g6 Y& UPage 1 (1)
4 u1 b6 U* T ]7 Q1 g/ I0 oSubject:; x' }: K; w# b" z1 v' x* k5 v
Hazardous Voltage
2 ]- K# D7 u/ w- ?* |- AKey words:/ s) o5 J( W9 v2 T
-Hazardous Voltage
1 q8 h" u2 I* l K* f- F! E( qDecision confirmed
8 e7 _& J: x; Q+ M! [at CTL 38th meeting
. L! o! ^+ g2 g9 xQuestion:8 e5 e4 D2 W* Q7 w( \3 R" C" @
Which of the criteria 42,4Vpeak or 60Vdc do you find should be applied as the compliance r/ a# `' T! W
criteria, in order to determine whether the voltage shown in the graph is hazardous or not?
: y5 s6 i8 d6 L; w; T- k) Q, oCondition: The circuit that generates this voltage is not a limited current circuit.( ]! @; m5 r2 {
Decision:, m; B( L4 V; i5 `" l5 ~
This voltage is a hazardous voltage because it exceeds the 42,4Vpeak as written in 1.2.8.32 a9 M7 A; H0 ~! `4 O# X# B: U
3 w! `% R/ n/ O) a) y; B% k1 N1 W/ s
9 v- r- w- _0 b' [( c
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发表于 2012-11-6 17:16
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