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[HOUS] DSH 440 Short-circuit of motor capacitors

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发表于 2012-9-14 13:07 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
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DSH 440  L. n$ `$ u) @1 ?
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Short-circuit of motor capacitors( v; x. T& j$ `9 g, c/ R( n0 }, l
19.7
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60335-1(ed.3)# _9 _2 R9 Q. L: p

0 @: f( Z4 P3 V5 ~/ w+ X8 mStandard: IEC60335-1:1991, 3rd Ed.7 n7 \1 q% B. W) O4 c( P; A
Sub-clause: 19.73 @) h1 Z9 t* O; _
Sheet No. DSH-4406 a4 A& ?: `. V6 f7 N
Subject: Short-circuit of motor capacitors: O# p, D/ U, _; \1 v7 S
Key words: -short circuit   -motor capacitor
+ i5 i1 u, t. N8 S1 zDecision taken at the 40th CTL meeting 2003.! r, K4 Q/ B: K! d6 g
Question:0 w! d# A' l1 |2 K, A1 I, U
TC 61 requested CTL to clarify the test procedure for short-circuiting capacitors in accordance with Sub" G: p- R1 q) ~
clause 19.7 of IEC 60335-1.
5 R) q& Q- f! A. `! S  {. BDecision:
! y7 h! `! R6 g1 q" m4 G5 X; BIf the design of the circuit is such that short-circuiting of one capacitor will result in the short-circuiting0 O/ Y$ w" y. q9 f! l0 k
of the second capacitor, only one capacitor needs to be short-circuited. This is endorsed by the sub clause
8 Q; {2 r) Q# I9 q" @; N6 w4.3 that states “If it is evident from the construction of the appliance that a particular test is not1 h% z0 ~+ M. e0 K7 r; V" X
applicable, the test is not made”.
7 Z: P0 \' f5 ^) {The followings are examples of the circuits.
4 \$ s; {0 f5 l* f1 |In the Example A:" d: a3 H8 e) ?* V- {' Q+ L. d; i4 k
Short-circuit of capacitor (Cb) terminals is necessary according to the requirements. For the
* A9 V' P2 R: S& t; c3 `capacitor (Ca), short-circuit of its terminals when motor is running is not necessary because
1 v$ {7 t; t* O/ ]$ vthe circuit is opened (the switch is opened).
  K$ e/ V' i4 ]8 h8 I# h5 |: p3 ~Also short circuit of its terminals (Ca) when the motor starts is not necessary because it is: i: R* H9 M4 {0 `1 G8 ^) G' j
already covered by the short-circuit of Cb terminals.7 c+ G& M+ _1 G* R
In the Example B:
( o4 g# x! R" `& h$ mOnly one short-circuit, either Cb1 or Cb2 terminals, is necessary because the testing of one
0 \  Y# U3 Q6 e1 b5 B( ~' u7 Kcovers the testing of the other one. Also the short-circuit of Ca terminals is not necessary
, Y4 e$ j( H- G# f' n) C# Wbecause of the reason stated in the Example A.
% c- \8 i# \& c/ b% X" E$ Y% O' x0 Q" e, y

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