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49 Component Power Measurement Test0 c9 S; W1 z4 B' Q6 {4 Z
49.1 To determine if a component or a circuit of a seasonal lighting product is capable of delivering 15/ C8 M1 S5 z; E8 N, a% i; Y: K
watts of power for one minute (see 48.1, Exception No. 1(c)), the component shall be tested as described! Q2 N, q, y$ }% b! a9 P6 i
in 49.2 – 49.4.
; k' [. `6 }' _# ]# Y) Y9 ^2 u2 c49.2 The unit is to be connected to a 60 Hz, 120 V supply source. One component or circuit of the unit
- V& I+ p. W, l. ]is to be connected to a wattmeter and an adjustable external load resistor as illustrated in Figure 49.1.
. f% \4 k8 Y. }( mThe external load resistor is to be set for its maximum resistance. A closed shorting switch is to be5 v0 I Y7 H2 B! i! x2 B
connected across the unit’s protective device, such as a fuse, and the resistor is then to be adjusted to9 F/ _4 N' d1 @- ~; t( ~
cause a power dissipation of exactly 15 watts as indicated by the meter. The shorting switch across the
6 z# N( k: d0 @protective device is then to be opened and the time required for the protective device to open is to be
( R% E- P! V5 w0 C- y: Yrecorded.6 I7 a1 P" c) g& B' }
49.3 During the test, the supply circuit is to be protected by a 20 A time delay fuse, with characteristics
& l+ d+ |3 ~/ z b6 f Fsuch that the fuse will not open in less than 12 seconds when carrying 40 A.
# ]( h3 D. {4 _& c3 Z5 z/ v: N) }49.4 The point of measurement of the circuit (see Figure 49.1) is not considered capable of delivering 15
) k- a' v( l8 N7 qwatts for one minute if:
4 P3 E3 u+ G; B6 C8 o$ B2 Ka) The protective device of the unit opens in less than 60 seconds,3 {* ~7 E3 y. E# @! ^
b) A circuit component opens in less than one minute, or; ?/ I" ?) D# W* P# H( W: m0 R
c) The current is inherently limited by the circuit. |
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发表于 2010-8-6 13:51
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