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|  DSH 387) o0 m4 ?5 k: t6 E; e
9 B* [& u; M W0 a6 r3 i! s a | Hazardous Voltage/ [, K( a+ u% L! T
| 1.2.8.3 / 12.8.4
* M+ P8 O3 r- O. { O- o! M, g | 60950(ed.2) & 60950(ed.3)
" \) G, d1 U2 K8 y s5 {2 L |
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Standard:
" Z; O8 G, Q1 `/ I5 |, P8 y5 MIEC60950, 2nd (3rd) Edition, R1 u' c$ @, J i% t8 d
Sub clause:
8 x/ n- j# `# X* I; }' u1.2.8.3(1.2.8.4)* k8 N' R+ ~; O; j
Sheet n. 387 [1 T2 ~3 j* L5 S1 ?/ P! J
Page 1 (1)! E: B# @& A& E |
Subject:0 U6 O8 Y. W! e+ i
Hazardous Voltage
# a2 X1 W' H1 s3 U Q$ ?Key words:
; G' x" R1 A+ O* ^$ P4 x' p3 l-Hazardous Voltage2 T5 F& |) m0 Y/ w# v6 \' g
Decision confirmed
2 U# e0 \8 s6 a7 ?0 cat CTL 38th meeting; V/ W0 X( p- O6 C
Question:
0 H9 z/ z! _1 w0 x) PWhich of the criteria 42,4Vpeak or 60Vdc do you find should be applied as the compliance
! Y4 n" C* {1 s+ Z( _. Pcriteria, in order to determine whether the voltage shown in the graph is hazardous or not?
7 r4 V$ d5 \6 f: w5 `8 O2 PCondition: The circuit that generates this voltage is not a limited current circuit.
- T6 W$ m) ] m+ P) |" p. NDecision:
6 e3 _3 L' q) P8 H7 LThis voltage is a hazardous voltage because it exceeds the 42,4Vpeak as written in 1.2.8.3
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" N% A1 |8 Y# u/ t; k4 K: C8 H. f: s! [% t6 [6 q. ^6 c
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发表于 2012-11-6 17:16
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