标题: 请教一个关于60335中导体线径问题 [打印本页] 作者: EN123 时间: 2007-8-5 01:00 标题: 请教一个关于60335中导体线径问题 3.1.6$ E7 n4 p- b. A
rated current5 J2 a5 r; G. |: t7 ~! h M
current assigned to the appliance by the manufacturer # f- M+ U1 y- [- wNOTE If no current is assigned to the appliance, the rated current is 0 y- |* h2 A; Y5 m– for heating appliances, the current calculated from the rated power input and the rated voltage; 6 U1 c1 p7 ]( O& e d* s- `; C– for motor-operated appliances and combined appliances, the current measured when the appliance is supplied at rated voltage and operated under normal operation. O& J. B6 ~- n( H- A# g; J " U( {; ?9 B1 | @5 l& ^# G4 h10.2, C/ K5 Z1 k3 {7 ~- Y6 u3 x
If an appliance is marked with rated current, the current at normal operating 4 _& g9 u" W6 ]" v" x/ w3 _/ O3 {9 Ytemperature shall not deviate from the rated current by more than the deviation shown in 3 U% H6 {( E1 R6 N' q8 itable 2. + _2 ^% l& D2 r- z# W: `/ f3 I& O, z6 R* G# h# H8 Y4 D. c3 ^* g
25.8 : ?! j: W2 m. B1 Z% i
Conductors of supply cords shall have a nominal cross-sectional area not less than ! D: F3 o& A' e6 }) ?8 Fthat shown in table 11.! f6 u6 D5 B) E2 c9 ]5 Q" x
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根据标准25.8中表格11描述导体的线径由额定电流决定；而额定电流又是由厂家定义（3.1.6）；并且额定电流按照10.2规定，可以有偏差。 ) ~# `% T) L& f. S; a6 t, Q5 K2 }5 y3 [/ g$ c' ]
问题：一个电动器具，厂家定义额定电压：230 V ～/50 Hz 额定电流：10A， 但实际测试10.2中电流为5A，按照10.2的规定电动器具额定电流大于1.5A只有正偏差的要求，则厂家这样定义符合要求。# H2 g- E+ m" A* h' l
在这种情况下，我们是按照实际测试的电流来决定电源线的线径或按厂家定义的额定电流来决定电源线的线径？如上面例子是至少0.75mm²的线径符合要求，还是按照厂家定义的额定电流至少要1.0mm²才符合要求？ # x ?# v: m* {4 A 6 d" H# [* m; ~) M另外，请问表格11规定的根据载流量来选择线径有引用哪一份标准吗？作者: caballo3157 时间: 2007-8-5 08:55
按额定电流，而不是实测电流。作者: hli168 时间: 2007-8-5 09:04
特殊规格有负偏差！额定电流不能按只按通用要求来定，还要结合特殊要求才可以的。3 i, c& Y3 ^ r! E% }. `" A
标准IEC60335-2-14的第3章如下： 7 X2 q2 Y* h& U' K0 j5 ]6 e3 Definitions 4 J6 s% Q% J" g' _; {2 W3 D jThis clause of Part 1 is applicable except as follows. : ^2 Y- `( R' o( s3 v& Y: D3.1.9 Replacement: 2 P1 Z9 s) h" [/ Q6 Mnormal operation g5 W8 _1 R) z# aoperation of the appliance under the conditions specified in 3.1.9.101 to 3.1.9.119, or at rated . ]) ?% o) m t( ~! g1 o! P5 I* y3 dpower input if this is more unfavourable $ r& |$ P5 f; T3 P9 O3 pNOTE 101 If the conditions are not specified, the appliance is operated with the most unfavourable load indicated + e/ v7 B2 U4 {8 sin the instructions.+ d, a' l: b) M; h; M
NOTE 102 Rated power input is obtained by applying a constant torque to the appliance placed in its normal 3 B/ N' c. H: V& o4 dposition of use and without subjecting it to imbalance forces greater than those occurring in normal use. , H: r( p% m, l0 @5 g# w! e5 c4 BNOTE 103 Operation at rated power input is considered to be more unfavourable if the power input determined 6 l& r6 N# H( Jduring the test of 10.1 differs from the rated power input by more than1 t- V* L' y; {
• –20 % for appliances having a rated power input not exceeding 300 W;4 R5 J( B# X; Q1 ~' {0 E
• –15 % (or –60 W if greater) for appliances having a rated power input exceeding 300 W.作者: huhaijun 时间: 2007-8-5 09:05
一个电动器具，厂家定义额定电压：230 V ～/50 Hz 额定电流：10A， 但实际测试10.2中电流为5A，按照10.2的规定电动器具额定电流大于1.5A只有正偏差的要求，则厂家这样定义符合要求。 6 k' ^0 J3 ?9 o; ]- n+ I' ^在这种情况下，我们是按照实际测试的电流来决定电源线的线径或按厂家定义的额定电流来决定电源线的线径？如上面例子是至少0.75mm²的线径符合要求，还是按照厂家定义的额定电流至少要1.0mm²才符合要求？2 w5 a, G8 p( ]' N
